Reverse Number logic

int given_no = 123, final_rev_no = 0, temp = 0,initialno;
initialno = given_no;
while (given_no > 0)
{
    temp = given_no % 10;
    final_rev_no = final_rev_no * 10 + temp;
    given_no /= 10;
}
lblmessgae.Text = "Reverse of given number is " + final_rev_no;

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